Compute the no. of distinct ways in which 56 toffees can be distributed to A,B,C,D,E so that no person receives less than 10 toffees?
A)10c6 B)10c5 C)6^3

• Distribute 10 toffees to each of 5 persons. so total 50 toffees , now remaining toffees are 6 which we hav to distribute among 5 person so this can be possible in
  6+5-1C5-1=10C4=10C6 so option will be A
  
• 11 years agoHelpfull: Yes(68) No(5)
• distribute 10 toffes to each first: after that 6 toffes (r),5 persons(n)
  (n+r-1)C(r-1)=10C5
• 11 years agoHelpfull: Yes(25) No(32)
• NO PERSON RECEIVES LESS THAN 10 TOFFEES
  so 50 toffees are distributed equally i.e 10 toffees to each of A,B,C,D,E
  now (56-50=6) toffees are to be distributed among 5 persons
  
  we know that
  number of ways in which n identical things can be distributed among r persons, each one of them can get 0,1,2 or more
  =(n+r-1)C(r-1)
  
  here n=6(toffee) is to distributed among r=5(persons)
  
  no. of ways=(6+5-1)C(5-1)=10C4=10C6
• 9 years agoHelpfull: Yes(17) No(0)
• @akanksha...
  this question was asked in elitmus...??
• 11 years agoHelpfull: Yes(15) No(8)
• (a+10)+(b+10)+(c+10)+(d+10)+(e+10)=56(all of them will receive atleast 10 toffee)
  a+b+c+d+e=6 (we distribyted 6 among 5 )total no. of ways 10c4=10c6
• 9 years agoHelpfull: Yes(2) No(0)
• distribute 10 coffee to each so total 50 toffees,and now remaining toffee are 6 and now we have to distribute 6 toffee in 5 person.let n=6,r=5 so total way is (n+r-1)C(r-1)=(6+5-1)C(5-1)
  =10C4.
  why i used this formula you can understand from this explanation.
  Consider that the number of identical objects as n.Now consider that all the n objects are placed on a row.Let us assume some separators that separates the n objects.Now as we want to separate them into r group[as blank groups are also allowed],take the separators as objects.Now we need r-1 separators to make r groups.Therefore total number of objects is n+r-1.There will be r-1 places for the separators to occupy.Therefore we can arrange the separators in
  (n+r-1)C(r-1) ways, which is the answer to the question asked.
• 8 years agoHelpfull: Yes(2) No(0)
• first we will distribute 10 toffees to each of 5 persons i.e total 50 toffees ,
  now remaining toffees are 6 which we have to distribute among 5 person so this can be possible in
  m+r-1 C r-1
  =>6+5-1C5-1=10C4
• 9 years agoHelpfull: Yes(1) No(0)
• option 4 is 5^6
  the ans is 5^6
• 6 years agoHelpfull: Yes(1) No(2)
• samjh nahi aaya...bhai solution...
• 9 years agoHelpfull: Yes(0) No(0)
• option a.is the ans
• 9 years agoHelpfull: Yes(0) No(0)
• NO PERSON RECEIVES LESS THAN 10 TOFFEES
  so 50 toffees are distributed equally i.e 10 toffees to each of A,B,C,D,E
  now (56-50=6) toffees are to be distributed among 5 persons
  
  we know that
  number of ways in which n identical things can be distributed among r persons, each one of them can get 0,1,2 or more
  =(n+r-1)C(r-1)
  
  here n=6(toffee) is to distributed among r=5(persons)
  
  no. of ways=(6+5-1)C(5-1)=10C4=10C6
  Read more at http://www.m4maths.com/17628-Compute-the-no-of-distinct-ways-in-which-56-toffees-can-be-distributed-to-A-B-C-D-E-so.html#3GwjU8Y8ft7ZtyiF.99
• 8 years agoHelpfull: Yes(0) No(4)
• a,b,c,d,e>10
  let us assume k>=1
  now a,b,c,d,e,k>=11
  So 11-1C6-1=10C5
• 7 years agoHelpfull: Yes(0) No(3)