Q. How many 3-digit numbers will be there which are divisible by 19?

• first digit : 19*6= 114 last digit=19*52=988
  
  a=114 l=988
  l=a+(n-1)d
  988=114+(n-1)19
  n=47.
• 11 years agoHelpfull: Yes(42) No(1)
• three digit nos starts from 100 to 999.
  so no of digits which are divisible by 19 =999-100= 899 => 899/19.
  quotient = 47.
• 10 years agoHelpfull: Yes(32) No(0)
• 114,133......988
  Tn=a+(n-1)d
  988=114+(n-1)19
  n=47
• 11 years agoHelpfull: Yes(16) No(1)
• ATQ :
  there should be 3 digit number,So First Digit=114
  Last digit which is divisible by 19 is 19*52=988
  
  Apply the formula of A.P....An=a+(n-1)d---------------Eq(1)
  
  Where An=988, a=114, common difference d= 19
  
  Applying above value in Eq(1) we get,
  
  988=114+(n-1)19
  
  874=19n-19
  
  893=19n
  
  n=893/19
  
  n=47
  
• 9 years agoHelpfull: Yes(1) No(0)
• Lets solve this in a different manner and in a quick way without using friends.I hope u will like it friends.
  
  The greatest three digit number is 999
  
  Now 999/19=52.57
  means simple up to 999 ,52 numbers are completely divisible by 19 including 5 two digit numbers also which are 19, 38 , 57 , 76 , 90.
  
  So required total 3 digits numbers are 52-5=47.
  Therefore 47 is the correct answer.Hare Krishna
• 8 years agoHelpfull: Yes(0) No(0)
• Sorry its formula instead of friends in first sentence.
• 8 years agoHelpfull: Yes(0) No(0)