An equilateral triangle ABC with sides of length Θ cm is placed inside a square AXYZ with sides
of length 2*Θ cm so that side AB of triangle is along the base of the square (as shown).
The triangle is rotated clockwise about B, then C and so on along the sides of the square until the points
A, B and C return to their original positions. Find the length of the path (in cm) traversed by point C.

• 7*pi*i
  explaination : point C travels distance equal to arc of circle of radius 'i' with degrees of 120 and 30....and to re-reach their home position it takes 3 rounds of complete triangle along the sides of the given square so final equation becomes like this-----3*((3*(2*pi*i)/3)+(2*(2*pi*i)/12))
• 11 years agoHelpfull: Yes(15) No(5)
• angular displacement of point c :120,120,30,30,120 degree in a full round and after 3 full rounds point c will return to its original position and other 2 point also to their respective positions...do check it...and distance covered = 3*((2*pi*I)/3+(2*pi*I)/3+(2*pi*I)/12+(2*pi*I)/12+(2*pi*I)/3)=7*pi*I
• 11 years agoHelpfull: Yes(7) No(4)
• what are options???
  
• 11 years agoHelpfull: Yes(0) No(5)
• its not exact 7*pi*i bt close to 7*pi*1...
  it wl take 3 full rounds n 5/9th part of a round more
  do tell me the rght ans
• 11 years agoHelpfull: Yes(0) No(2)
• can sb explain in detail??how u people r relating it wid circle??plz do explain it in a bit more ellaborative way..thnks in advance.
• 11 years agoHelpfull: Yes(0) No(1)