The number 27P5216R is divisible by 45 and P,R>0. What is P+R?
(1)13
(2)4
(3)17
(4)15
(5)None of these

• 13
  
  P=8
  R=5
  
  In 27P5216R, R should be 5 as number is multiple of 5.
  so 27P5216R becomes 27P52165.
  Now 27P52165 is divisible by 9.
  sum of digits should be divisible by 9.
  so P=8 so that sum of digits =36.
  27P5216R = 27852165
• 12 years agoHelpfull: Yes(1) No(0)
• 13
  
  divisible by 45 => Divisible by 9 and 5
  
  Divisible by 5 => R = 0 or 5
  but R > 0 => R = 5
  
  Divisible by 9 => sum of digits divisible by 9
  => (2 + 7 + P + 5 + 2 + 1 + 6 + R) = (23 + P + R) divisible by 9
  
  => P + R = 13
• 12 years agoHelpfull: Yes(1) No(1)