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Maths Puzzle
The number 27P5216R is divisible by 45 and P,R>0. What is P+R?
(1)13
(2)4
(3)17
(4)15
(5)None of these
Read Solution (Total 2)
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- 13
P=8
R=5
In 27P5216R, R should be 5 as number is multiple of 5.
so 27P5216R becomes 27P52165.
Now 27P52165 is divisible by 9.
sum of digits should be divisible by 9.
so P=8 so that sum of digits =36.
27P5216R = 27852165 - 11 years agoHelpfull: Yes(1) No(0)
- 13
divisible by 45 => Divisible by 9 and 5
Divisible by 5 => R = 0 or 5
but R > 0 => R = 5
Divisible by 9 => sum of digits divisible by 9
=> (2 + 7 + P + 5 + 2 + 1 + 6 + R) = (23 + P + R) divisible by 9
=> P + R = 13 - 11 years agoHelpfull: Yes(1) No(1)
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