a container of production line solvent is mixed at 22% strength and another is mixed at 53% strength.to obtain 12 liter of a mixture that is 25% strength,how many liter should be used from the container that is mixed at 53% strength?
a)4 liters
b)1 5/31liters
c)2 16/25 liters
d)5 35/53 liters
e)4/59

• ans 1 5/31
  
  simply use the shortcut link up process for finding the ratio.
  
  22 53
  25
  (53-25) (25-22)
  28 3
  
  so the ratio should be 28:3
  so 53% strength solvent is 12*3/31
  36/31
• 11 years agoHelpfull: Yes(70) No(25)
• let 22% solution is x liter,
  then 53% solution is 12-x liter for 12 liter solution
  
  reqired average solution is 25%
  
  therefore,
  
  22x+53(12-x)=25*12
  22x-53x=300-636
  31x=336
  x=10.839
  thus 10.839 liter solution of 22% strength
  and (12-10.839)=1.161 liter solution of 53% stregth
• 8 years agoHelpfull: Yes(7) No(0)
• 12*25=300
  300/53= 5 35/53
  
• 9 years agoHelpfull: Yes(4) No(6)
• using alligation
  A B
  22 53
  25
  28 3
  
  so from second container (12*3)/31=36/31=1.16 ltr will be mixed
• 9 years agoHelpfull: Yes(1) No(0)