ome Students are arranged equidistantly in circular order and numbered 1,2,3…. . It is observed that 12 is opposite to 40. There are 10 girls more than boys. How many maximum number of boys can be opposite to girls??
a) 15 b)23 c)24 d)28

• ans should be (b)23
  12 is opposite of 40 means 27 students having both sides
  so, 27+27+2=56
  and 10 girls more than boys
  so 23 boys nd 33 girls
• 11 years agoHelpfull: Yes(27) No(2)
• as 12 and 40 are exactily opposite 40-12=28 is the half of the students
  then total students --> 28+28=56.
  As 10 girls are more than boys. lets take those 10 girls out so we gat equal no of boys and girls
  --> 56-10=46.
  so nof boys is half of 46 --> 23 and gils are 33..
  so max no of boys pop to girls is 23
• 11 years agoHelpfull: Yes(13) No(0)
• since 40 is opposite
  therefore 40-13=27 both side
  total student=27*2+2=56
  a+b=56
  a+10=b
  by solving a=23,b=33
  so no. of boys=23
• 11 years agoHelpfull: Yes(7) No(0)
• cant understand this..........
• 11 years agoHelpfull: Yes(1) No(0)