IBM
Company
Numerical Ability
Sequence and Series
1/5,1/2,1/3,2/5,1,2/3,3/5,1 1/2,1,4/5
Read Solution (Total 7)
-
- 1st series= (1/5, 2/5, 3/5, 4/5)
diff bwn each term= -1/5
2nd series= (1/2, 1, 1 1/2, x)= (0.5, 1, 1.5, 2) => x=2
diff bwn each term= -0.5
3rd series= (1/3, 2/3, 1, x)= > x=4/3
diff bwn each term= -1/3
ans = 2 - 11 years agoHelpfull: Yes(49) No(5)
- Ans= 4/2=2
- 11 years agoHelpfull: Yes(8) No(0)
- i think question is not correct in place of 11/2 it shud be 3/2 then its answer will be 2
- 11 years agoHelpfull: Yes(5) No(3)
- its mixed fraction 1 1/2= 3/2= 1.5
- 11 years agoHelpfull: Yes(4) No(7)
- answer is 2
- 10 years agoHelpfull: Yes(2) No(0)
- I am sure answer given by SHALINI D R IS RIGHT ;-)
- 8 years agoHelpfull: Yes(0) No(0)
- How 11/2 =1.5
- 7 years agoHelpfull: Yes(0) No(1)
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8,5,9,7,2,2.5,5,1,16,8,4