There is a 4-character code, with 2 of them being letters and the other 2 being numbers.
How many maximum attempts would be necessary to find the correct code? Note that the code is case-sensitive.

• It is an example of Permetutation and Combination. There are 26 alphabets and 10 digits
  Hence, the maximum attempts will be 26C2*10*2 = 14625 ways.
• 5 years agoHelpfull: Yes(0) No(1)
• Actually its case sensitive therefore,
  2* (26C2) *(10 C2) = 29250
• 5 years agoHelpfull: Yes(0) No(0)