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Logical Reasoning
Number Series
1. Given the following functions
(1) f(n a b c ) = ac if n=1
(2) f(n a b c) = f( n-1 a c b) + f( 1 a b c) + f( n-1 b a c ) if n > 1
Then what is the value f( 4 a b c ) = ?
Read Solution (Total 4)
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- f( 4 a b c ) = 5*(ab+bc+ca)
f(2 a b c) = f( 1 a c b) + f( 1 a b c) + f( 1 b a c ) =ab+bc+ca
f(3 a b c) = f( 2 a c b) + f( 1 a b c) + f( 2 b a c ) = 2(ab+bc+ca)+ac
f(4 a b c) = f( 3 a c b) + f( 1 a b c) + f( 3 b a c ) = 5*(ab+bc+ca)
- 11 years agoHelpfull: Yes(34) No(10)
- 4(ab+bc+ca)+3ac
bcz:
f(3 a b c)=2(ab+bc+ca)+ac (fro leena)
f(4 a b c)=f(3 a c b)+f(1 a b c)+f(3 a b c)
2(ab+bc+ca)+ac+ac+2(ab+bc+ca)+ac
=4(ab+bc+ca)+3ac - 11 years agoHelpfull: Yes(13) No(1)
- ans=15ac......
- 11 years agoHelpfull: Yes(1) No(16)
- f(4 a b c)=f(3 a c b)+f(1 a b c)+f(3 b a c)
f(4 a b c)=f(3 a c b)+ac+f(3 b a c)
f(4 a b c)=3acb+ac+3bac
f(4 a b c)=ac*(6b+1) - 6 years agoHelpfull: Yes(0) No(0)
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