IN a lawn,grass grows equally thick and uniform rate every day.It takes 24days for 70 cows to graze and 60 days for 30 cows.How many cows are required to graze lawn in 96 days.

• 20 cows
  
  If C is the amount of grass eaten by one cow every day
  and G is amt of grass growing every day,
  x is the initial amount of grass, then
  x+24G= 70*24*C
  x+60G= 30*60*C
  solving, G = (10/3)*C
  x= 1600C
  If n cows are required to graze lawn in 96 days,
  1600C+ 96G= 96*n*C
  1600C+320C=96nC
  n=20 cows
• 11 years agoHelpfull: Yes(76) No(12)
• i dont undrestnd solution plz explain
• 11 years agoHelpfull: Yes(21) No(4)
• 70 cows work x+24y
  30 cows work x+60y
  
  (x+24y)*70=30*(x+60y)
  x=3y
  for 96 days suppose k cows require
  x+96y=99y
  99y*k=63y*30
  k=20
• 11 years agoHelpfull: Yes(9) No(7)
• very good@aman
• 11 years agoHelpfull: Yes(2) No(2)
• this is simple steps
  12days-->35 cows
  24days-->70 cows
  30days-->60 cows
  ----------------------------
  96 days---->135cows answer
  
• 9 years agoHelpfull: Yes(1) No(37)
• Let initially X grass was present there,and it is increasing by Y grass per day, then for the first condition We get,
  X+24*y = 24*70 ----(1)
  For the 2nd condition, we have,
  X+60*Y = 60*30----(2) Now, On solving equation (1) and (2), we get
  X = 1600 and
  Y = 10 /3
  Third Condition,
  X+96*Y = 96 *N -----(3) [N = Number of Cows required]
  Putting the values of X and Y in equation (3), We get
  N = 20.
• 7 years agoHelpfull: Yes(1) No(0)