A cask full of milk is taken E liters of milk is replaced with water This process is repeated again

let total volume of milk be x...for first step E amount in removed so remaining volume x-E.......again repeating the steps .....x-2E.......according to question (x-2E)/2E=16/9, on solving x= 5.5E~5E
11 years agoHelpfull: Yes(8) No(4)
Let volume of cask be V ltr
so,
16/(16+9)=(1-E/V)^2
=> V=5E Ans.
11 years agoHelpfull: Yes(6) No(0)
It will depend on E .

capacity = 5E
5E..0... Initially
4E..E ... After first replacement
3.2E ...1.8E.. after 2nd replacement
11 years agoHelpfull: Yes(3) No(5)
let the milk qty be x
E liter is replaced with water
x-E/E RATIO after first exchange
x-2E/2E ratio after 2nd exchange
.
.
.
after n exchange x-nE/nE=16/9
x/nE=25/9
x=25/9(nE)
can't be determined as it isn't mentioned the no of time process is repeated..
11 years agoHelpfull: Yes(1) No(0)
total milk content =16*100/25=64litrs
total water content =9*100/25=36litrs
total cask is of 100 litrs
consider E=4 so total is 25*4 = 100
ans is 25E
11 years agoHelpfull: Yes(0) No(3)
formula- the qty of milk at end of process/total capacity of cask=(X-E/X)^2
or, 16/16+9=(X-E/X)^2
or, (4/5)^2=(X-E/X)^2
or, (X-E)/X=4/5
or, 5X-5E=4X
X=5E therefore, volume of cask=5E
8 years agoHelpfull: Yes(0) No(0)

A cask full of milk is taken. E liters of milk is replaced with water. This process is repeated again. Ratio of milk to water is 16:9 at the end of process. Find volume of cask??