pradeep mixes two mixtureof milk and water.he mixes 40 ltr of the 1st containing 20% water,and 60 ltr of 2nd containing 30% of water,find the % of water in final mixture

• Ans=26%
  Amount of Water in First Mixture=40*20/100=8 Liters
  Amount of Water in Second Mixture=60*30/100=18 Liters
  Total Amount of Mixture=40+60=100 Liters
  & amount of Water=8+18=26 Liters, which is 26%
  
• 11 years agoHelpfull: Yes(16) No(2)
• 1st mixture havin=40*20/100 ie 8 ltr water
  2nd mixtre havin=60*30/100 ie 18
  total =26 ltr water in 100 ltr mixture
  no need to calculate %
  we can directly say 26%
• 11 years agoHelpfull: Yes(5) No(2)
• Ans= 26%
  1st mixture 40 lit with 20% of water so water quantity=8 lit
  2nd mixture 60 lit with 30% of water so water quantity=18 lit
  total mixture 100 lit out of which 26 lit is water...
  so get the answer... wish u al d best...
• 11 years agoHelpfull: Yes(2) No(0)
• 40*20/100 = 8
  40-8= 32
  60*30/100=18
  60-18= 42
  tottal water= 18+8= 26 ltr..
• 11 years agoHelpfull: Yes(2) No(0)
• 40+8=48
  60+18=78
  48+78=126
• 11 years agoHelpfull: Yes(0) No(10)
• first mixture contain water=20% of 40ltr =8
  second mixture contain water =30 of 60ltr=18
  percentage of water in new mixture=((8+18)/(60+40))*100
  =26%
  this is answer
  
• 11 years agoHelpfull: Yes(0) No(0)
• water contained in 40 ltrs=40x20/100=8 ltrs
  water contained in 60 ltrs=60x30/100=18 ltrs
  Therefore total water contained in (40+60)=100 ltrs of mixture=(8+18)=26 ltrs
  so,the % of water in the mixture would be 26%
  
• 11 years agoHelpfull: Yes(0) No(0)
• 40 ltr->20% water=8 ltr of water
  60 ltr->30% water=18 ltr of water
  40+60=100
  8+18=26
  26/100*100=26% of water in total
• 11 years agoHelpfull: Yes(0) No(0)
• 26% in first there will be 8 ltr water
  in 2nd there will be 18 ltr water
  total =26 litr which is 26% of 100
• 11 years agoHelpfull: Yes(0) No(0)