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Q. Two trains running at x meters per second and y meters per second cross the same tunnel in a seconds and b seconds respectively. If the difference of lengths in the trains is m meters, then-Option
Option
A) m=xa - yb
B) 1/m=1/(xa) + 1/(yb)
C) m=xa + yb
D) m/(xa)=yb + 1Q
Read Solution (Total 1)
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- length of trains will be xa-t and yb-t where t is length of tunnel.
m=xa - yb - 11 years agoHelpfull: Yes(1) No(1)
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