The average age of A,B,C and D is 58 years. If the average of B,C,D and E is 60 yrs and the ages of A and E are in the ratio of 7:8, the age of E is
a)64 yrs
b)62 yrs
c)66 yrs
d)63 yrs
e)61 yrs

• ABCD averg age 58
  ABCD total age 4*58=232
  A+B+C+D=232....eqn 1
  BCDE avg age 60
  BCDE total age 4*60=240
  B+C+D+E=240...eqn 2
  eqn(2)-eqn(1)
  E-A=8....eqn 3
  A ad E age ratio 7:8
  A/E=7/8
  A=7E/8..sub eqn (3)
  E-(7E/8)=8
  (8E-7E)/8=8
  E=64
• 11 years agoHelpfull: Yes(3) No(1)
• *Correction : the ratio is 7:8
• 11 years agoHelpfull: Yes(2) No(0)
• A+B+C+D=232.... (1)
  B+C+D+E=240.... (2)
  eqn(2)-eqn(1)
  E-A=8....eqn 3
  A ad E age ratio 7:8
  A/E=7/8
  A=7E/8..sub eqn (3)
  E-(7E/8)=8
  (8E-7E)/8=8
  E=64
• 11 years agoHelpfull: Yes(1) No(0)
• (A+B+C+D)=4*58=232
  (B+C+D+E)=4*60=240
  A:E=7X:8X
  then 232-7X=240-8X
  X=8
  then E=8X=8*8=64
  
• 11 years agoHelpfull: Yes(1) No(0)
• ABCD averg age 58
  ABCD total age 4*58=232
  A+B+C+D=232....eqn 1
  BCDE avg age 60
  BCDE total age 4*60=240
  B+C+D+E=240...eqn 2
  eqn(2)-eqn(1)
  E-A=8....eqn 3
  A ad E age ratio 7:8
  A/E=7/8
  A=7E/8..sub eqn (3)
  E-(7E/8)=8
  (8E-7E)/8=8
  E=64
• 11 years agoHelpfull: Yes(0) No(0)