The average of marks obtained by 120 candidates was 35. If the average of passed candidates was 39 and that of failes candidates was 15, the number of candidates who passed the examination is
a)100
b)110
c)120
d)150
e)170

• no.of pass=p
  no.of fail=120-p
  total marks=pass+fail
  120*35=39p+(120-p)*15
  solvng we get p=100
• 11 years agoHelpfull: Yes(16) No(3)
• a) 100
  
  m = 100 , n = 20
• 11 years agoHelpfull: Yes(4) No(5)
• number of passed candidates = m
  number of failed candidates = n
  total marks of passed candidates = p
  total marks of failed candidates = f
  
  => (p + f) = 120 * 35 ,
  m + n = 120
  p = 39m
  f = 15n
  
  solving these , m = 20
  
• 11 years agoHelpfull: Yes(2) No(3)
• 39 15
  /
  35
  /
  20 4
  
  20:4=5:1...
  
  who passed ==5/6*120=100
• 11 years agoHelpfull: Yes(1) No(3)