The average of a number,its square and its cube is two more than the fourteen times the number.
Find the number?

• If number is x, then
  (x+x^2+x^3)/3= 14x+2
  x^3+x^2+x= 42x+6
  x(x^2+x-41)=6
  solving, we get
  x=6
• 11 years agoHelpfull: Yes(2) No(0)
• Let the unknown number be x. As per the given condition, the equation becomes:
  (x+x^2+x^3)/3=2+14*x
  => x+x^2+x^3 = 6 + 42*x
  => x^3+x^2-41*x=6
  => x(x^2+x-41)=6
  Solving the equation, we get x=6
• 11 years agoHelpfull: Yes(1) No(1)
• no is 6
  6+36+216=258/3=86
  14*6=256+2=258
• 11 years agoHelpfull: Yes(0) No(0)