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Maths Puzzle
The average of a number,its square and its cube is two more than the fourteen times the number.
Find the number?
Read Solution (Total 3)
-
- If number is x, then
(x+x^2+x^3)/3= 14x+2
x^3+x^2+x= 42x+6
x(x^2+x-41)=6
solving, we get
x=6 - 11 years agoHelpfull: Yes(2) No(0)
- Let the unknown number be x. As per the given condition, the equation becomes:
(x+x^2+x^3)/3=2+14*x
=> x+x^2+x^3 = 6 + 42*x
=> x^3+x^2-41*x=6
=> x(x^2+x-41)=6
Solving the equation, we get x=6 - 11 years agoHelpfull: Yes(1) No(1)
- no is 6
6+36+216=258/3=86
14*6=256+2=258 - 11 years agoHelpfull: Yes(0) No(0)
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