Elitmus
Exam
Numerical Ability
Permutation and Combination
. In a class of 39 students the ratio of boys and girls is 2 : 1. Radhika ranks 15th among all the students from top and 8th among girls from bottom. How many boys are there below Radhika?
(1) 16 (2) 17
(3) 15 (4) Data inadequate
(5) None of these
Read Solution (Total 13)
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- 17 boys
total 26 boys and 13 girls.
7 girls are at bottom
5 girls are above Radhika.
so 9 boys are above Radhika.
so out of 26 boys, 17 boys are below Radhika. - 11 years agoHelpfull: Yes(112) No(0)
- total student= 39, boys : girls = 2:1, hence no of boys= 2/3(39)= 26
num of girls= 1/3(39) = 13 , since radhika ranked 15 among 39 student from top
and ranked 8 among girls from bottom , this means 7 girls are below radhika, rest 13-9= 5 girls are above her, now from 14 toper 5 are girls hence 14-5=9 boys.
hence num of boys below radhika are 26-9=17 - 11 years agoHelpfull: Yes(28) No(1)
- in class there are 39 students.
boys:girls=2:1
so boys=26 , girls=13
now radhika ranked 8th among girls from bottom. so there are 7 girls below radhika....at the same time she is 15th ranked student from top...so we know there are only 13 girls and 7 of them are bellow radhika. so 13-(7+1)=5 girls are above radhika..and from top radhika is 15th..so assuming 5 girls on top of radhika there are 14-5=9 boys...
total boys in the class=26
top of radhika 9 boys..
so 26-9=17 boys are below radhika.
(2)17 is correct answer. - 11 years agoHelpfull: Yes(12) No(0)
- ANS:17
I.E.,5 GIRLS,9 BOYS IN TOP OF RADHIKA
I.E.,7 GIRLS,17 BOYS IN BOTTOM OF RADHIKA - 11 years agoHelpfull: Yes(9) No(0)
- the correct answer is 17.
Since Radhika ranks 15th in class so the students below her are 39-15=24..and there is 7 girls below Radhika
so 24-7-17 boys the right answer - 11 years agoHelpfull: Yes(4) No(1)
- no of boys =2/3 x 39 = 26
no of girls = 1/3 x 39 = 13
position of radhika is 15th from top ,
therefore 14 students are ahead of her which can be boys and girls.
she ranks 8th from bottom in girls means 7 girls are below her.
so no of girls ahead of radhika is=
total no of girls - radhika + girls below her
13-1+7=5
therfore no of boys a head of radhika = 14-5 .....{postion of radhika is 15th from top}
= 9
total below her 26-9 =17
required no of boys. 17
- 10 years agoHelpfull: Yes(1) No(0)
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- 16 boys
total 26 boys and 13 girls
if radhika is 8th among girls from bottom,then she has 4girls above her.
she is 15th from top, out of which there are 4girls above her.
that means she has 10boys above her.
so remaining boys 26-10=16boys are below her. - 11 years agoHelpfull: Yes(0) No(30)
- answer :17 boys below radhika
total 39 students
ratio=2:1
boys=(2*39)/3=26
girls=(1*39)/3;=13
radhika rank is 15th from top among all i.e 14 students are above from it .
so we have to find how many boys and girls are above from radhika .
radhika is 8th from buttom then from top=13-8+1=6
i.e 6th from top 5 girls are above from radikha
then no. of boys up from radhika=14-5=9
remaning boys=26-9=17 boys.. - 9 years agoHelpfull: Yes(0) No(1)
- ans is 19 boyz are below radhika so option 5 none of these
- 9 years agoHelpfull: Yes(0) No(10)
- It's not a p and c problem.
- 7 years agoHelpfull: Yes(0) No(0)
- Radhika ranks 15th in class from above
so the students below her are 39-15=24
and there is 7 girls below Radhika
so 24-7-17 boys is the answer - 2 years agoHelpfull: Yes(0) No(0)
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