Elitmus
Exam
Numerical Ability
Time and Work
A is a creater nd B is a destroyer. A can complete a building in 20 days while B can destroy it in 30 days. If both working alternate days,then after how much time will be the building completes for the first time?
Read Solution (Total 13)
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- Ans)115 days
A 1 day=+1/20
B 1 day=-1/30
In 2 days building will be complete 1/20-1/30=1/60
so days are reqired=120...but
If full building work is 1, then before B destroy ,A complete the building .so
completed building work before A finished =>(1-1/20)=19/20 ,this will gives the number of pair A,B works...
consider x is number of pair days work of A,B...
1/60*x=19/20=>x=57;
so number of days=2 * pair days ;
number of days A and B work =114;
at last A done ramaining work, so 114+1=115
Ans)115 days
- 11 years agoHelpfull: Yes(57) No(3)
- 115
A's 1 day=+1/20
B's 1 day=-1/30
In 2 days building will be complete 1/20-1/30=1/60
(1-1/20 = ) 19/20 part of wall will be made in 114 days.
on 115th day balance 1/20 th will be made by creator.
- 11 years agoHelpfull: Yes(30) No(4)
- Let us say that the wall is of 60 bricks
A builds 3 bricks every day
B destroys 2 bricks every day
If A and B work on alternate days then 1 brick will be added every 2 days.
After 114 days, 57 bricks will be added. Now it will be turn of A to build 3 bricks. Hence on 115th day 60 bricks will be completed - 10 years agoHelpfull: Yes(19) No(0)
- A's 1 day=+1/20
B's 1 day=-1/30
In 2 days building will be complete 1/20-1/30=1/60
2 days =1/60
=>2*60 days=1
i.e it require 120 days.... - 11 years agoHelpfull: Yes(10) No(33)
- in 2 days they complete building 1/60 part.so they both complete in 120 days
- 11 years agoHelpfull: Yes(4) No(19)
- one day creation of the A is =1/20
one day destruction of the B is =1/30
so 2 day construction is=1/20-1/30=1/60
to complete work each take 60 turn
so days are reqired=120 - 11 years agoHelpfull: Yes(4) No(18)
- a does 1/20 work in 1 day
b destroys 1/30 work in 1 day.
together they do 1/20-1/30 work in one day that is 1/60 work
hence they take 60 days to complete building - 11 years agoHelpfull: Yes(3) No(23)
- Lets say total work to be done is LCM of 20&30 which is 60 UNIT.
A's work for 1 day is 60/20=3 UNIT.
B's work for one day is 60/30=2 UNIT but negative or -2 unit.
now here A starts first because B demolishes , or demolition only can be done if there is some work already done.
so here (A+B) will be a pair for two days work which yields 1 unit work in 2 days.
hence this will continue for 114 days which will yield 57 unit work but on the end of 115th day the works will be 60 unit or 100% hence the work will be first completed on 115th day.
HENCE answer is 115 day
- 8 years agoHelpfull: Yes(3) No(0)
- can anyone explain why the solution shouldn't stop at 120 days?
- 11 years agoHelpfull: Yes(0) No(4)
- Days Efficiency
A - 20(days) ----- 5% (100/20)
B - 30(days) ----- -3.33% (100/30)
Total efficiency in 2 days = 1.66
Building will be completed when eff =100;
( 100 / 1.66 )*2 = 120 days - 11 years agoHelpfull: Yes(0) No(5)
- correct answer=120
short cut method:
days total unit
60
a=20 3
b=30 - 2
total one day work=1
here a start the work so pattern like ab ab ab......
so one pattern work=60
so 60/1=60 pattern
one pattern =2 days
so 60 pattern 2*60=120 days is the correct answer
total work 12
- 8 years agoHelpfull: Yes(0) No(2)
- A one days work 1/20= 5%
B one day work 1/30 = -3.33%
2 day's work = 5-3.33= 1.68%
They work together until they complete the 95% work and final 5% would be done by A itself
1.68*x=95
x=114
now A will do the remaining 5% of work in last day it would be = 114+1= 115 - 7 years agoHelpfull: Yes(0) No(0)
- let total unit of work is 60 unit
then A do 3 nit of work in 1 day and B do 2 unit of work in 1 day
resultant nit of work = 3-2=1 unit per day
it takes 57 days to complete 57 unit of work...... as next day A do 3 unit of work and it reaches 60 unit(total work)
hence total 57+1= 58 days required to complete the building for the first time :P - 7 years agoHelpfull: Yes(0) No(0)
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