rectify the previous question of probability the number was x 4 4

(x^4 + 4) to be divisible by 5
=> last digit of x^4 = 1 or 6
=> possible last digit of x = (1,2,3,4,6,7,8,9)
where (0 , 5) are not possible

number of 4 digit numbers from 1000 to 9999 = 9000

(1000 , 1005 ,1010 , 1015 ... 9995) are not possible i.e. excluding 1800 numbers ,
possible outcomes = 9000 - 1800 = 7200

=> probability = 7200 / 9000 = 3/4
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1/8.
The answer can be found out using the 4th term in the power series of all digits.
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I m having elitmus exam on sunday...plz mail me all questions at sumitrawal586@gmail.com
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I m having elitmus exam on sunday...plz mail me all questions at ghoshsambitstet@gmail.com
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probability will be 4/5 x^4+4 divisble by 5
no will be divisble by 5 onlt if last digit is 0 or 5
except no having last digit 0 or 5 all no having power 4 yield last digit 1 or 6 when added 4 its last digit will be o or 5
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rectify the previous question of probability ..the number was (x^4 + 4)