find the probability distribution of the number of successes in two tosses of a die, where a success is defined as
i) no. greater than 4
ii) 6 appears on at least one die

• 1. 8/9
  2. 1/3
• 11 years agoHelpfull: Yes(0) No(1)
• (i) Sample space is 1,2,3,4,5,6
  probability of getting no. greater than 4 in firs toss is 2/6 =1/3
  so probability of getting no. less than 4 is 1-1/3=2/3
  Let X denote the no of successe in two tosses of a die. Then x can be 0,1,2
  so p(X=0)=probability of no success in first and 2nd toss both =2/3*2/3=4/9
  p(X=1)=prob. of success in first and failure in 2nd or vice versa.
  = 1/3*2/3+2/3*1/3=4/9
  p(x=2)= prob. of success in both toss =1/3*1/3 =1/9
  so probability dist. is
  X; 0 1 2
  P(X); 4/9 4/9 1/9
• 11 years agoHelpfull: Yes(0) No(1)
• 1)2/6*2/6=1/9
  2)1/6+1/36=7/36
• 11 years agoHelpfull: Yes(0) No(1)