AIEEE
Exam
Numerical Ability
Probability
A can hit a target 4 times in 5 shots B three times in 4 shots and C twice
in 3 shots. They fire a volley. What is the probability that atleast two shots
hit.
Read Solution (Total 2)
-
- I am not sure but I 'll try.
A's prob of hitting shot = 4/5
B's prob of hitting shot = 3/4
C's prob of hitting shot= 2/3
probability that atleast two shots hit = 4/5 * 3/4 + 3/4*2/3 = 2/3 * 4/5 = 3/5 + 1/2 + 8/15 = 49/15
- 11 years agoHelpfull: Yes(4) No(5)
- A's prob of hitting shot = 4/5 prob not hit = 1/5
B's prob of hitting shot = 3/4 prob not hit = 1/4
C's prob of hitting shot= 2/3 prob not hit = 1/3
atleast 2 means 2 or 3 if 2 hit and one not and all 2 hit
probability that atleast two shots hit = 4/5 * 3/4 *1/3 + 3/4 * 2/3 *1/5+2/3*4/5*1/4 + 2/3*4/5*1/4 = 5/6 - 11 years agoHelpfull: Yes(3) No(4)
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