A man travels by bus for 20 hours and they by train for 05 hours . if the average speed of the bus was 20 kmph and that of the entire journey was 24 kmph. What was the average speed of the train?

(A) 44kmph
(B) 30 kmph
(C) 36 kmph
(D) 40 kmph

• Total distance travelled = 24*(20+5)= 600 kms
  distance travelled by bus = 20*20=400 kms
  distance travelled by train = 600-400=200kms
  av speed of train = 200/5=40 kmph
• 11 years agoHelpfull: Yes(29) No(0)
• 40 kmph
  
  distance travelled in bus = d1
  distance travelled in train = d2
  speed of train = s2
  Speed of bus = 20Kmph
  average speed of journey = 24kmph
  
  Avg speed = (d1 + d2) / (T1 + T2)
  => 24 = (20*20 + 5*s2) / (20 + 5)
  => 600 = 400 + 5*s2
  => s2 = speed of train = 40 kmph
• 11 years agoHelpfull: Yes(4) No(7)
• (20*20)+5x/25=24
  solve for x we get 40kmph
  
• 11 years agoHelpfull: Yes(2) No(0)
• here (20*20+x*5)/25=24
  400+5x=600
  x=40
• 11 years agoHelpfull: Yes(2) No(1)
• avg speed of bus=20kmph
  let avg speed of train=x
  then avg speed of journey =2(20)(x)/[20+x] = 24
  solve for x, x=30kmph
• 7 years agoHelpfull: Yes(0) No(0)