there are three players playing an chess competetion at a time only 2 players can play the chess game and player A wins 15 games player B wins 14 games and player c wins 9 games ..
so who played the 11 th match and how many games did player C lost .

• A wins 15 game,, B wins 14,,C wins 9 game...if A WIN 15 GAME so B AND C both are responsible for loose 15 because they dont loose how can A win...therefore B+C=15 LOST game similarly A+C=14 LOST GAME also B+A=9 GAME LOST ..so we have three equation of lost game 1)B+C=15 2)A+C=14 and 3)A+B=9 solving 1 and 2 we get B-A=1--(4) eqn,,,,,solving 2 and 3 we get C-B=5--(5)eqn ,, now solve 4 and 5 we get C-A=6--(6) eqn....yes we get answer by solving 6 eqn with 2 eqn we get C=10 Therfore C LOST 10 GAMES/.....
• 11 years agoHelpfull: Yes(28) No(1)
• can u explain it properly kripal how c lost 16 or 25 games along with game order
• 11 years agoHelpfull: Yes(4) No(5)
• c loss 29 games
  
• 11 years agoHelpfull: Yes(3) No(13)
• c lost 25 games
• 11 years agoHelpfull: Yes(0) No(6)
• c lost 16 games......
• 11 years agoHelpfull: Yes(0) No(6)