If x^(a-b)=16 ,x^a=64 y^b=3 & x-y=175, then a+b=?

• its 1.
  x^a/x^b=16,64/x^b=16,x^b=4.
  x^b=4 and y^b=3
  by trial and error method
  x=256 and y=81
  and 256^b=4 so b is 1/4
  x^(a-b)=16 so 256^(a-1/4)=16
  solve for a then a=3/4 so ans is 3/4+1/4 its 1
  
  
• 11 years agoHelpfull: Yes(1) No(0)