There are 3 piles each contain 10 15 20 stones. There are A,B,C,D,F,G and H persons. One man can catch unto four stones from any pile. The last man who takes will win. If first A starts next B. and so on who will win?

• F WILL WIN
• 10 years agoHelpfull: Yes(7) No(0)
• There are total 10+15+20 = 45 stones. There are seven persons( A to H, except E). That is maximum stones they can take is 28. Since there is excess of stones, H will always win. Even if there were 8 persons (A to H), then also H will win, as it then requires that there be only 32 stones.
• 15 years agoHelpfull: Yes(4) No(20)
• from 1st pile 10/4=2
  from second pile 15/4=3
  from third pile 20/4=5
  2+3+5=10
  A,B,C,D,E,F,G,H,I,J
  J WILL WIN THE GAME
• 10 years agoHelpfull: Yes(1) No(8)
• D will win
• 8 years agoHelpfull: Yes(0) No(1)
• The answer is F. F will win
• 7 years agoHelpfull: Yes(0) No(0)