One type of liquid contains 25% of Kerosene, the other contains 30% of Kerosene. P can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of the Kerosene in the new mixture.

28%
25%
30%
27%

• Let P be filled by 60 lts of 1st liquid and 40 lts. of 2nd liquid.
  
  amount of kerosene = (25*60/100) + (30*40/100) = 27 lts.
  
  % of kerosene = 27 %
• 11 years agoHelpfull: Yes(20) No(0)
• 6*(25/100)+4*(30/100)
  =27/100
  Ans: 27%
• 11 years agoHelpfull: Yes(2) No(0)
• 25%,30%
  6 parts, 4 parts so it is 6:4
  (25*6/10)+(30*4/10)=27%
• 11 years agoHelpfull: Yes(1) No(0)
• let 1 part is = 100 liters
  1 part of 1st liquid contains 25 liters of kerosene
  1 part of second liquid contains 30 liters of kerosene
  so 6 parts and 4 parts of 1st and 2nd contains 25*6+30*4=270
  so 270/1000=27%
• 11 years agoHelpfull: Yes(0) No(0)