A starts 3min after B for a place 4.5 km distant B on reaching his destination immediately returns and after walking a km meets A. If A can walk 1km in 18min, then what is B's speed?

5kmph
4kmph
6kmph
3.5kmph

• 5 kmph
  If speed of B is x kms/min, then
  (4.5+1)/x= [3.5/(1/18)] +3
  x=1/12 km/min= 5 kms/hr
• 11 years agoHelpfull: Yes(14) No(10)
• @deepanya
  
  a walks 3.5km and b walks 4.5+1=5.5km
  a can walk 1km in 18min so for 3.5km --> 3.5*18=63min
  b starts before 3min than a so b takes 63min+3min=66min for 5.5km
  so b speed is 5 km/h.
• 11 years agoHelpfull: Yes(11) No(0)
• A travels 3.5 kms in 63 minutes(3.5*18)
  and
  B travels 5.5 kms
  B started 3 minutes earlier than A,B takes 66 minutes to complete 5.5kms
  In 60 minutes he covers 5kms
  
• 11 years agoHelpfull: Yes(8) No(2)
• Can u explain me clearly dipin or anyone
• 11 years agoHelpfull: Yes(4) No(1)