In two alloys, copper and tin are related in the ratios of 4:1 and 1:3. 10kg of Ist alloy, 16 kg of 2nd alloy and some pure copper melted together. An alloy obtained in which the ratio of copper and tin was 3:2. Find the weight of the new alloy.

34kg
35kg
36kg
30kg

• suppose x kg of pure copper is melted with 10kg of Ist alloy and 16 kg of 2nd alloy , then
  Pure cooper in new alloy = 10*4/5 + 16*1/4 +x = 12+x kg
  Pure tin in new alloy = 10*1/5+ 16*3/4 = 14 kg
  As per given condition
  (12+x)/14 = 3/2
  24+2x= 42
  x=9 kg
  
  Total weight of new alloy = 10+16+9=35 kg
• 11 years agoHelpfull: Yes(83) No(1)
• In 1kg of 1st alloy copper =800gm and tin =200gm
  in 2nd alloy 1kg contains copper =250 gm and tin -750 gm
  10 kg of 1st alloy + 16 kg of second alloy contains copper = 8000+4000=12000
  and tin = 14000
  given (12000+x)/14000=(3/2)
  24000+2x=42000
  x=9000
  total weight=12000+9000+14000=35000=35kg
• 11 years agoHelpfull: Yes(5) No(0)
• after melting together,
  there would be 12KG of copper, 14KG of tin and some pure copper,let it be 'x'.
  From given data,
  (12+x):14 = 3:2
  => 24+2x=42 => x = 9
  i.e,9Kg pure copper is added(melted) with two alloys.
  now weight of new alloy = 10 + 16 + 9
  = 35 kg
• 11 years agoHelpfull: Yes(2) No(1)