A bag contains Rs.102/- in the form of rupee,50paise and 10paise coins in the ratio 3:4:10.what is the number of 10 paise coins?

• Initially consider 3x:4y:10z but y=x/2 and z=x/10.
  so 3x+4(x/2)+10(x/10)=102
  3x+2x+x=102
  6x=102
  x=17.
  Implies 3*17 =51 rupee coins
  4*17 = 68 fifty paise(34 rupee)
  10*17 =170 ten paise coins(17 rupee)
  ..51+34+17=102/-
• 10 years agoHelpfull: Yes(23) No(0)
• 170 coins
  coins of rupee,50 paise and 10 paise are 51,68,170 respectively.
• 11 years agoHelpfull: Yes(8) No(0)
• 3x+2x+x=102
  6x=102
  x=17
  so 170
  
• 10 years agoHelpfull: Yes(6) No(0)
• total amount = 102;
  3x + 4x / 2 + 10x/10 = 102
  6x = 102
  x = 17;
  no. of 10 paise coins = 170
• 10 years agoHelpfull: Yes(2) No(0)
• Let the no of 1rupee,50 paise and 10 paise coins are 3x,4x and 10x respectively.
  So, 100*3x+50*4x+10*10x = 102*100
  Or, x = 17
  So, The no of 10 paise coins are 10*17=170
• 10 years agoHelpfull: Yes(2) No(0)
• 520 10 paise coins
  coins 30,40,520
• 10 years agoHelpfull: Yes(1) No(1)
• 3x+0.5*x*4+0.1*x*10=102
  solving above equation..x=17
  we require 10x..10*17=170
• 10 years agoHelpfull: Yes(1) No(0)
• 170 coins
  repee,50 paise,paise....>>>51,68,170
• 10 years agoHelpfull: Yes(1) No(0)
• Let no of 1 rupee is 3x;
  no of 50 paise is 4x;
  no of 50 paise is 10x;
  
  therefore 3x*1+4x*.50+10x*.10=106
  =>6x=106
  =>x=17
  
  therefore no of ten(10) paise in 10*17=170 (Ans)
• 10 years agoHelpfull: Yes(1) No(1)
• 3:4:10 means 3 +2+1=6 rupee
  to make 6 rupee we take 10 coins of 10 paise
  so for 6 --- 10
  102 --- ?
  
  =1020/6= 170
• 10 years agoHelpfull: Yes(1) No(0)
• 170
  3x*100+4x*50+10x*10=10200
  by solving them we get x=17
  therefore no.of 10 paisa coins=10x=10*17=170
• 9 years agoHelpfull: Yes(1) No(1)
• number of 10 paise coins are 10*102/5.10=200
• 10 years agoHelpfull: Yes(0) No(0)
• 170 coins....
  
• 10 years agoHelpfull: Yes(0) No(0)
• 170
  51*1=51
  68*.5=34
  170*0.1=17
  total=102
  
  
  
• 10 years agoHelpfull: Yes(0) No(1)
• (3:4:10)*20 =>
  
  60:80:200 = 60+40+2 = 102/-
  
  Ans : 200
  
• 10 years agoHelpfull: Yes(0) No(1)
• the number of 10 paise coins will be 200
  i.e, 60:80:200 in the ratio of rupee,50 paise and 10 paise
• 10 years agoHelpfull: Yes(0) No(0)
• 3x+(4x/2)+(10x/10)=102;
  x=17
  no of 10 paise coin=17*10=170
• 10 years agoHelpfull: Yes(0) No(0)
• 4x+2x+x=102
  x=17
  therefor there are 170 10paisa coins
• 10 years agoHelpfull: Yes(0) No(1)
• 3X*1 + 4X*0.50 +10X*0.10=102
  
  X(3+2+1)=102
  
  X=102/6=17
  
  10 paise coins=17*10=170
• 10 years agoHelpfull: Yes(0) No(0)
• 170 10paisecoins are there because...
  let x be the no.of coins (multiple of ratio)
  3x 1rupee
  4x 50paise
  10x 10paise
  total constitute 102/-
  3x*1 + 4x* 1/2 + 10x * 1 /10=102
  x=17
  10paise coins are 10x so, 170coins.
• 10 years agoHelpfull: Yes(0) No(0)
• Assume coin as 3x,4x,10x then
  
  3x *1 + 4x* (1/2) + 10x* (1/10)= 102
  by solving x=17
  so the 10 paise coins are 170
• 9 years agoHelpfull: Yes(0) No(0)
• 10/17*102=60
• 9 years agoHelpfull: Yes(0) No(0)
• 17
  1rs= 1
  50ps=1/2
  10ps=1/10
  a(3+4*1/2+10*1/10)=102
  a=17
  so there are 17*3=51 1 rs coin
  68 50ps coin
  170 10 ps coin
• 9 years agoHelpfull: Yes(0) No(0)
• difference is 10 so that next number is 31
• 6 years agoHelpfull: Yes(0) No(0)
• Ratio of number of coins of -
  
  1 rupee : 50 paisa : 10 paisa = 3 : 4 : 10
  
  ∴ Ratio of total values of coins of-
  
  1 rupee : 50 paisa : 10 paisa = (100 × 3) : (50 × 4) : (10 × 10) = 3 : 2 : 1
  
  Total value of 10 paisa coins in Rs 102-
  
  = 1/(3+2+1) × Rs 102
  
  = Rs 102/6 = Rs 17
  
  = 1700 paisa
  
  ∴ Number of 10 paisa coins = 1700/10 = 170
  
  Hence, the required number of 10 paisa coins is 170
• 1 year agoHelpfull: Yes(0) No(0)