A person bought 76 cows and sold 20 cows at 15 profit 40 cows at 19 profit and remaining 16

Let cost price of each cow is x.
20x*0.15+40x*0.19+16x*0.25=6570
solving x=90
So the cost of each cow is Rs. 90.
11 years agoHelpfull: Yes(1) No(6)
Ans=450 Rs.
If the cost of each cow is x, then cost of 76 cows=76x
Given 20x*1.15+40x*1.19+16x*1.25=76x+6570 or
4x(5.75+11.9+5.00)=76x+6570 or 90.60x=76x+6570 =>14.6x=6570 or x=450
11 years agoHelpfull: Yes(1) No(1)
let the cost of each cow is x Rs.so
(20x)*(15/100)+(40x)*(19/100)+(16x)*(25/100)=6570
x is comman.so
x(14.6)=6570
x=450
So the cost of each cow is Rs 450.
11 years agoHelpfull: Yes(1) No(1)
ans =rs 450
suppose cost of each cow be x.
cp of 20 cow =20x;
sp of 20 cow= (115/100)*20x=23x;
profit = 23x-20x=3x;
again
cp 40 cow =40x;
sp = (119/100)*40x= 238x/5;
profit= 238x/5-40x= 38x/5;

cp of 16 cow =16x
sp= (125/100)*16x=20x
profit=20x-16x;
total profit=3x+38x/5+4x;
A/Q
3x+38x/5+4x=6570
=>x= (6570*5)/73= 450
11 years agoHelpfull: Yes(0) No(0)

A person bought 76 cows and sold 20 cows at 15% profit 40 cows at 19% profit and remaining 16 cows at 25% profit and got a profit of 6570 as a whole . the cost of each cow is ?