How many 5 digit numbers N are there, such that the digit sum of N is 43, and N is divisible by 11?

• As sum of digits is 43,
  5 digits can be
  9,9,9,9,7
  or
  9,9,9,8,8
  Difference of sum of digits at even places and odd places should be 11.
  so numbers will be of type
  9X9X9
  where Xs can be replaced by 8,8 or 9,7 or 7,9.
  
  so only 3 combinations are possible to get 97999, 99979 and 98989.
  
• 11 years agoHelpfull: Yes(6) No(1)
• 3
  
  97999, 99979 and 98989 are the 3 numbers divisible by 11 with sum of digits 43.
• 11 years agoHelpfull: Yes(2) No(0)
• Good question and well explained answer.
  
  seems correct.
• 11 years agoHelpfull: Yes(2) No(0)
• can you explain KARAN how you got this ?
• 11 years agoHelpfull: Yes(0) No(2)