general
Maths Puzzle
There are 3 persons X, Y and Z. On some day, X lent tractors to Y and Z as many as they had. After a month Y gave as many tractors to X and Z as many as they have. After a month Z did the same thing. At the end of this transaction each one of them had 24.
Find the tractors each originally had?
Read Solution (Total 5)
-
- Going from back , XYZ ...24,24,24.... one step earlier ....12,12,48,... one step earlier ...6,42,24.... one step earlier ( at first stage ) ....39,21,12
- 14 years agoHelpfull: Yes(14) No(1)
- 39,21,12
- 14 years agoHelpfull: Yes(1) No(0)
- 39,21,12
- 14 years agoHelpfull: Yes(1) No(0)
- X=39,Y=21,Z=12
- 14 years agoHelpfull: Yes(0) No(1)
- 12z,21y,39x cause if x give them twice what they have it would be 24z,42y,and leave 6x then y doubles what z and x have 48z,12y, and 12x then z does the same 24z,24y and 24x so the anwser is 12z,21y,and 39x
- 13 years agoHelpfull: Yes(0) No(1)
general Other Question