A cistern is normally filled in 8 hrs,but takes 2 hrs longer to fill because of a leak on its bottom,if Cistern is full ,how much time citern would empty?

• Ans=40 Hrs.
  If leakage/hour=1/x, then 1/8 -1/x= 1/10, solving 1/x=1/40
  So in 40 hours full cistern will be empty.
• 11 years agoHelpfull: Yes(22) No(4)
• work done to leak in 1hour =1/8-1/10
  " =1/40
  so,total time it require 2 empty the cistern =40 hours
• 10 years agoHelpfull: Yes(4) No(0)
• 40 hrs
• 11 years agoHelpfull: Yes(3) No(7)
• ans: 11-0!=10
• 8 years agoHelpfull: Yes(0) No(0)
• the total time taken to fill is 10hrs including leakage time
  so consider the cistern empty time is x
  1/10=1/8-1-x
  1/x=1/40
  so 40hrs
• 5 years agoHelpfull: Yes(0) No(0)