Renuka got married 8 years ago. Today her age is 4/3 times of marriage. Her daughter age is 1/8 times her age. her daughter age is
(a)3 years
(b)4 years
(c)6 years
(d)8 years
Explain it please!

• answer is 4yrs.let renuka age at time of marriage is "x"now her age is x+8.now x+8=4/3(x) i.e x=24..so her daughter age be "y" .given y=18(x+8) on substition of "x" we get y=4.
• 11 years agoHelpfull: Yes(8) No(0)
• Renuka got married 8 years ago. Today her age is 4/3 times of marriage.
  If her age at time of marriage was x, then
  x*4/3 = x+8x/3=8
  x=24 yrs
  Her present age = 24+8=32 yrs
  Daughter's age = 32/8= 4 years
• 11 years agoHelpfull: Yes(6) No(2)
• Go with backtracking method..
  her daughter's age is 4 yrs means=(32/8)
  her mother's age is 32 years now.
  let at the time of marriage her age was x.
  so according to ques, x*4/3=32
  or, x=24
  so at the time of her marriage her age was 24 yrs
  after 8 yrs means now her age is 32
  and her daughter's age is 4
• 11 years agoHelpfull: Yes(4) No(4)
• ans:b)4 years
• 11 years agoHelpfull: Yes(1) No(3)
• let the age of RENUKA at the time of married is x
  then
  present age is (x+8); as per question (x+8)=4x/3;so x=24 ;so age of daughter is
  1/8*(x+8)=32/8=4
  ans=4
• 11 years agoHelpfull: Yes(1) No(0)