ABCD are four point in a plane such that ABD and DBC form two triangle. area of ABD is 10 unit and area of BDC is 20 unit. what is the ratio of length (AD/DC)

• base is common for both of the triangles
  area(abd)/area(bdc)=10/20
  =>(1/2)*bd*h1)/(1/2*bd*h2)=1/2
  =>h1/h2=1/2
  h1 and h2 are parallel (as they are perpendicular 2 same line)
  from this we can say that,
  respective angles are same for both the triangle.
  so ,
  ad/dc=1/2 (ans)
  
• 11 years agoHelpfull: Yes(11) No(18)
• ABCD are four points in a plane such that ABD and DBC form two triangles. Area of ABD is 10 units and area of BDC is 20 units. What is the ration of lengths (AD/DC)?
  i) Points ADC are collinear
  ii) DB is 5 units long and is perpendicular to AC.
• 7 years agoHelpfull: Yes(11) No(3)
• If ABC are in a straight line and DB is perpendicular to ABC, then
  AD/DC= sqrt(41/89)
• 11 years agoHelpfull: Yes(2) No(9)
• shalu - triangle is not a right triangle so we cannot apply this 1/2 base height
  and two diagrams can be made ....
  i m confused
• 11 years agoHelpfull: Yes(2) No(3)
• Sugandh according to your question(data sufficiency) ,the answer will be choice B (the question can be answered by either stmt alone)
• 5 years agoHelpfull: Yes(2) No(0)
• the answer is 1/2
  
• 11 years agoHelpfull: Yes(0) No(5)
• navneet plz give me your mobile number i want to talk plzzzzzz help me
• 11 years agoHelpfull: Yes(0) No(1)
• Area of triangle ABD = 2 * Area of Triangle BDC
  from this condition,
  AD/DC = 1/2
• 11 years agoHelpfull: Yes(0) No(3)