Q. In a company 6 boys and 8 girls can do work in 10 days 26 boys &48 women will do in2 days find time taken by 15 boys and 20 girls to do same work

• see shortcut....
  6b+8g=1/10
  =>3b+4g=1/20
  =>15b+20g=1/4
  =>4 days
  
• 9 years agoHelpfull: Yes(10) No(0)
• ans=4days
  let x= 1 day work of 1 boy
  let y= 1 day work of 1 girl
  we get 2 equations:
  6x+8y = (1/10) and 26x+48y = (1/2)
  solving 2 equations give:
  x=(1/100) and y=(1/200)
  now, 1 day work of 15 boys and 20 girls = 15x+20y= (1/4)
  thus, total days taken = 4 days.
• 10 years agoHelpfull: Yes(7) No(3)
• so easy...
  6boys+8girls=10days eq1
  26boys+48girls=2days
  
  so by simplifying
  10(6boys+8girls)=1day
  2(26boys+48girls)=1day
  
  so 60boys+80girls= 52boys+96girls
  solving above we will get 1boy=2girls
  
  now put it in eq1
  so it will be 12girls+8girls=10days
  20girls=10days
  den 15boys+20girls which is equal to 30girls+20girls will do it
  20*10/50=4days
• 10 years agoHelpfull: Yes(0) No(3)
• eqution 1 is 6x+8y=1/10
  2nd is 26x+48y=1/2.
  so x=1/100 and y=1/200
  then
  x=15*1/100
  y=2*1/200
  answer=4 day
• 10 years agoHelpfull: Yes(0) No(1)
• (6B+8g)10=(26B+48W)2
  =>
  60B+80g=........
  15*4B+20*4G=...... //divide from 2 , 2 times and 15 from 60
  
  (15B+20G)4=......
  
  it means 4 days
• 6 years agoHelpfull: Yes(0) No(0)