Q. 6 boysand 8 girls can do job in 10 days ,26 boys & 48 women do work in 2 days find time taken by 15 boys and 20 girls to do same work

• 6b+8g=1/10(1 day work) ------>(I)
  26b+48w=1/2 -------->(II)
  
  Divide both sides by 2 in (I) and multiply both sides by 5
  now we get
  15b+20b=1/4
  so ans. is 4 days.
  
  There is no use of (II) equation.
  
• 11 years agoHelpfull: Yes(44) No(4)
• suppose 1 boy can complete the work in x days and 1 girl can complete the work in y days
  Therefore, 6x + 8y = 1/10 (1 day work for 6 boys and 8 girls)
  and 26x + 48y = 1/2 (1 day work for 26 boys and 48 girls)
  now, on solving the above two equation we get
  x= 1/100 and y= 1/200
  thun on putting the value of x and y in 15x+20y we can get the ans i.e. 4 days
• 11 years agoHelpfull: Yes(14) No(1)
• 6boys & 8girls 1 day job=1/10
  26boys & 48 girls 1 day job=1/2
  so, 6b+8g=1/10
  & 26b+48g=1/2 solve htese 2 equation you will get b=1/100 & g=1/200.
  then look in question they are asking for 15 b& 20 g so,(1/15/100)+(1/20/200)=4 days
  
• 11 years agoHelpfull: Yes(10) No(1)
• 10(6b+8g)=2(26b+48g) (equal work done by both)
  solving this equation, we get 1b=2g
  substituting value in 26b+48g=2 days
  ie. 100g= 2 days
  hence comparing 50g will take 4 days
• 11 years agoHelpfull: Yes(4) No(2)
• 15-0.5(20)=5,the number of boys must be with half the number of girls
• 11 years agoHelpfull: Yes(0) No(13)
• 6x+8y=10
  26x+48y=2
  by solving x=5.8 y=-3.1
  15x+20y=
  15(5.8)+20(-3.1)=15 days
• 11 years agoHelpfull: Yes(0) No(15)
• no of days*pepole=work
  60b+80g=52b+96g ratio becomes b:g 1:2
  
  60(1)+80(2)= 220(work)
  (15(1)+20(2))x=220
  by solving dis we will get answer 4
  
• 11 years agoHelpfull: Yes(0) No(1)