Q. A 200M LONG GOODS TRAIN CROSSES A MAN STANDING ON THE PLATFORM A A SPEED OF 48KM/HR . AT THE SAME TIME ANOTHER GOODS TRAIN 150 METRES LONG CROSSES THAT MAN AT A SPEED OF 60KM/HR IN THE REVERSE DIRECTION. ALCULATE THE DIFFERENCE BETWEEN TIME TAKEN BY BOTH THE TRAINS TO CROOSS THE MAN

• Time taken by A 200M LONG GOODS TRAIN to CROSS A MAN STANDING ON THE PLATFORM at a SPEED OF 48KM/HR = 200/(48*5/18) = 15 secs
  Time taken by A 150 M LONG GOODS TRAIN to CROSS A MAN STANDING ON THE PLATFORM at a SPEED OF 60KM/HR = 150/(60*5/18)= 9 secs
  
  Difference in time = 15-9= 6secs
• 11 years agoHelpfull: Yes(12) No(2)
• Time taken by A 200M LONG GOODS TRAIN to CROSS A MAN STANDING ON THE PLATFORM at a SPEED OF 48KM/HR = 200/(48*5/18) = 15 secs
  Time taken by A 150 M LONG GOODS TRAIN to CROSS A MAN STANDING ON THE PLATFORM at a SPEED OF 60KM/HR = 200/(60*5/18)= 12 secs
  
  Difference in time = 15-12= 3secs
• 11 years agoHelpfull: Yes(3) No(4)
• Time taken by A 200M LONG GOODS TRAIN to CROSS A MAN STANDING ON THE PLATFORM at a SPEED OF 48KM/HR = ((3600/48000)*200)=15 sec
  Time taken by A 150 M LONG GOODS TRAIN to CROSS A MAN STANDING ON THE PLATFORM at a SPEED OF 60KM/HR = ((3600/60000)*150))=9 sec
  Difference in time = (15-9)= 6secs
• 11 years agoHelpfull: Yes(0) No(1)
• 35s dnt talk
• 11 years agoHelpfull: Yes(0) No(0)