Elitmus
Exam
Numerical Ability
Permutation and Combination
compute the number of distinct ways in which 56 toffees can be distributed to Amit, Badri, Chetan, Duti, Erwin so that no person receives less than 10 toffees
a 10c6
b 10c5
Read Solution (Total 5)
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- No person should get less than 10 toffees.
so 50 toffees are distributed equally.
rest 6 toffes are to be distributed among 5 .
n=6(toffes) r=5(person)
(n+r-1)C(r-1)=(6+5-1)C(5-1)=(10)C(4)=(10)C(6) - 11 years agoHelpfull: Yes(56) No(1)
- nCr = selection of n distinct object r at a time.
But here 6 toffees identical. so we use (n+r-1 C r-1).
Here n=6,r=5
6+5-1 C 5-1 = 10 C 4 = 10 C 4
ans= a.10 c 6 - 9 years agoHelpfull: Yes(4) No(0)
- No person should get less than 10 toffees.
so 50 toffees are distributed equally.
Rest 6 toffees are to be distributed .
To distribute 6 toffes (r), among 5 persons(n)
(n+r-1)C(r-1)=10C5 ways - 11 years agoHelpfull: Yes(3) No(32)
- Each person should get atleast 10 toffees. So, 50 toffees are distributed equally among 5 people i.e 10 toffees to each person. 6 toffees are left now.
Number of ways of distributing n identical things among r persons when each person may get any
number of things = (n + r – 1) C (r–1)
Therefore, 6 identical toffees are distributed among 5 people i.e n=6 and r=5.
=> (n + r – 1) C (r–1)
=> (6+5-1) C (5-1)
= 10 C 6 - 7 years agoHelpfull: Yes(2) No(0)
- 6c5.....as 6 toffees are to be distributed among 5 persons. please correct me if i am wrong :)
- 9 years agoHelpfull: Yes(0) No(12)
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