if both 117 and 88 are factors of the number a*47*64*1313, then what is the smallest possible value of a?

a 10296
b 429
c 90
d 9

• We can write a*47*64*1313=a*47*8*8*13*101
  So the number would have factors 117(13*9) and 88(11*8) if both should be in this no.
  To get these nos as factorial of the no we should have one extra 9 and 11 atleast.So the no 10296 has that extra 9 and 11.
• 11 years agoHelpfull: Yes(29) No(2)
• 117 =13*9
  88=11*8
  
  11*9=99 is smallest possible value of a.
• 11 years agoHelpfull: Yes(15) No(7)
• if both 117 and 88 are factors, it should divide a*47*64*1313 and remainder should be 0
  a*47*64*1313 be divisible by 117*88
  on simplifying
  a*47*8*101 be divisible by 9*11
  go through options now
  least no divisible by 11 and 9
  10296
• 11 years agoHelpfull: Yes(12) No(1)
• 99 is the answer.
  a * 47 * 8 * 8 * 13 * 101 is the number.
  as 88 and 117 are two factors i.e 8*11 and 13*9 are two factors, 11 and 9 are missing in the given number so 11*9 = 99 will be a.
• 11 years agoHelpfull: Yes(7) No(6)
• Ans is 10296.bcoz we require 11& 9 and it is in the no 10296.
• 11 years agoHelpfull: Yes(2) No(1)
• @Sumit 99 is the minimum number i agree...but acc to the options ans should be a)10296
• 11 years agoHelpfull: Yes(2) No(0)
• 10296
  
  117=3*3*13;
  88=11*8;
  10296 is divisible by 9 & 11; 1313 divisible by 13; 64 is divisible by 8
• 10 years agoHelpfull: Yes(2) No(0)
• 99 is the correct answer, option C is 99. please correct it.
• 7 years agoHelpfull: Yes(1) No(0)
• a.10296 will be the ans
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• a.10296
  117=3*3*13;
  88=11*8;
  10296
  is divisible by 9 & 11;
  1313 divisible by 13;
  64divisible by 8;
• 10 years agoHelpfull: Yes(0) No(0)
• a would be equal to the multiplication or (divide) by both no becase these are the factor of the no
  hence from the option only option (a) is suited.
  ans= 10296
• 10 years agoHelpfull: Yes(0) No(0)