AGE
* OAT
________
SOAR
HOG-
GOTO--
________
GECOIR

• 317
  *538
  -------
  **2536
  **951*
  1585**
  ----------
  170546
• 11 years agoHelpfull: Yes(10) No(8)
• thats an easy 1....
  
  try to refer this material for cryptarithmetic problems.
  http://cryptarithmetic.wordpress.com/
• 11 years agoHelpfull: Yes(3) No(0)
• (i)Consider O+O+O=O, it's only possible iff O=0 or 5 but O=0 is not possible therefore O=5;Substitute the value in problem
  
  (ii)Consider S+H+T=C, but since S+H+T cannot be greater than 27 therefore it cannot generate carry greater than 2 therefore E is either 6 or 7. But O*E=O i.e.
  5*E(6 or 7)=5 therefore since E=6 is not possible E=7; Substitute in problem.
  
  (iii)Consider O*A(i.e. 5*A = GE(including some carry from O*G(i.e.5*G)), therefore 1
• 11 years agoHelpfull: Yes(3) No(0)
• ITS AN EASY ONE...
  C=0,G=1,S=2,A=3,I=4,O=5,R=6,E=7,T=8,H=9
• 11 years agoHelpfull: Yes(2) No(4)
• rohit wil u plz give me your no. I want to talk to u plzzz...
• 11 years agoHelpfull: Yes(0) No(0)
• @ Pawan,
  
  You can give ur number. I shall call you later.
• 11 years agoHelpfull: Yes(0) No(0)
• 9908680424
• 11 years agoHelpfull: Yes(0) No(0)
• how to solve this kind of problems , plz some one suggest me which material study to solve !!
• 11 years agoHelpfull: Yes(0) No(0)
• Hi Rohit, please tell me hoe to solve this type problem....
  i wan tlk to u sir.
  plze give me your contact number/ Email....plzzeee....sir.
• 11 years agoHelpfull: Yes(0) No(0)
• pavan please give me ur no. or email id ......
• 11 years agoHelpfull: Yes(0) No(0)
• ROHITH CAN U PLZZ TELL ME HOW TO SOLVE THESE TYPE OF PROBLEMS..... MY MAIL ID IS murali.kummitha@gmail.com
• 11 years agoHelpfull: Yes(0) No(0)
• AGE
  * OAT
  ________
  SOAR
• 11 years agoHelpfull: Yes(0) No(0)
• explain each alphabet how it s assigned by numbers pls.......
• 11 years agoHelpfull: Yes(0) No(0)
• 317
  *538
  -------
  **2536
  **951*
  1585**
  ----------
  170546
  
  to solve this multiply indivisually T WITH= T*E=R,T*G=A,T*A=SO......(1)
  multiply indivisually A WITH= A*E=G,A*G=O,A*A=H........(2)
  multiply indivisually O WITH= O*E=O,O*G=T,O*A=GO.......(3)
  
  Consider O+O+O=O, it's only possible if O=0 or 5 but O=0 is not possible BECOZ if we multiply 0 with AGE then all value of GOTO will be same ot means 0
  AGE
  * 0AT
  ________
  SOAR
  HOG-
  0000--
  ________
  GECOIR
  here we had seen the changes while putting value if o is 0
  therefore O=5;Substitute the value in problem
  
  now its became:
  AGE
  * 5AT
  ________
  S5AR
  H5G-
  G5T5--
  ________
  GEC5IR
  
  multiply indivisually T WITH= T*E=R,T*G=A,T*A=S5......(1)
  multiply indivisually A WITH= A*E=G,A*G=5,A*A=H........(2)
  multiply indivisually 5 WITH= 5*E=5,5*G=T,5*A=G5.......(3)
  
  
  here we insert o=5
  
  to solve this question easily we take equation 3 indivisually.
  multiply indivisually 5 WITH= 5*E=5,5*G=T,5*A=G5.......(3)
  
  5*E=_5
  5*G+_=_T
  5*A+_=G5
  
  WHERE _ Is carry.
  
  using hit & trial method
  5*7=35
  5*1+3=8
  5*3+0=15
  
  after getting result of 3rdd equation
  
  you put this values in equation.
  
  
  317
  *5AT
  ________
  SOAR
  H5G-
  1585--
  ________
  G7C5IR
  
  put valus of agec in all places
  
  HERE IN 2ND step u had seen that when u put a=3 then u get the values of equation 2....
  
  
  317
  *53T
  ________
  S53R
  951-
  1585--
  ________
  17C5IR
  NOW PUT THE VALUES IN EQUATION 1
  U WILL GET OUTPUT.
  317
  *538
  -------
  **2536
  **951*
  1585**
  ----------
  170546
  
  
  
• 10 years agoHelpfull: Yes(0) No(0)