Q. At 10 am 2 trains started travelling towards each other from station 287 miles apart they passed each other at 1:30 pmthe same dayy .if average speed of the faster train exceeded by 6 miles /hr what is speed of faster train in miles/hr

• let the speed of slower train is x
  then speed of faster train is=x+6
  now, 287/x+x+6=7/2(3 and half hour)
  after solving the equation we will get x=38
  so faster train=x+6
  38+6=44
• 11 years agoHelpfull: Yes(35) No(0)
• we will come to know that they each travel for 3.30 hrs= 7/2 hrs
  sum of the distances traveled by both = 287 miles
  s1, s2 are the speeds of the faster and slower train respectively
  
  s1*(7/2)+s2*(7/2)=287...........(1)
  
  given that s1=s2+6.................(2)
  
  by solving (1)&(2)
  s1= 44 miles/hr
• 11 years agoHelpfull: Yes(14) No(0)
• let the speed of slower train be x
  then the faster train will be x+6
  difference in time is 3hr30 min=3.5hr
  speed=distance/time
  so,287=x*3.5+(x+6)*3.5=44 miles
• 11 years agoHelpfull: Yes(5) No(0)
• the ans is 44 miles/hr
  suppose the speed of slow train is x miles/hr,
  then the speed of the fast train would be x+6 miles/hr.
  now, they have traveled 287 miles
  and the time taken would be 3 hours and 30 minute or 7/2 hour.
  Thus applying the formula
  Speed=(Distance / Time)
  (x+(x+6))=(287/(7/2)).....eq (1)
  by solving the above we get the ans as 44 miles/hour
• 11 years agoHelpfull: Yes(4) No(0)
• let the speed of slowest train be x miles/hr
  speed of fastest train be x+6 miles/hr
  now,
  d/t=speed
  287/3.5=82
  then,x+x+6=82
  x=38
  fastest train speed will be x+6=44 miles/hr
• 10 years agoHelpfull: Yes(1) No(0)