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2 trains in sme direction at 50k/hr,32 k/hr.A man in slower train observes 15 sec elapse before the faster train completely passed by him what is length of faster train
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- relative speed= 18k/hr= 5 m/sec
distance covered= length of faster train= 5*15= 75meters - 11 years agoHelpfull: Yes(43) No(2)
- (50-32)=18k/hr then 18*5/18 k/hr =5m/sec
distance covered=length of the faster train=5*15=75
- 9 years agoHelpfull: Yes(4) No(0)
- Relative spped:18km/hr
I.e:5m/s
Dist covers=Len of fast train
5*15 =75 - 8 years agoHelpfull: Yes(0) No(0)
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