Sum of 50 numbers is 490. If greatest number is 20 more than the least. Least number is 0 and repeated twice then the average of remaining 47 numbers will be

• greatest num=20
  ither two numbers are 0,0
  so excluding 3 numbers, sum of 47 numbers is 470
  avg=470/47=10
• 11 years agoHelpfull: Yes(3) No(1)
• greatest no=20
  least no =0
  It is repeated twice so sum of 3 nos=20+0+0=20
  sum of remaining 47 nos=490-20=470
  so avg of remainig 47 no=470/47=10
• 11 years agoHelpfull: Yes(2) No(0)
• sum of 50 numbers is 490 and greatest no =20 + least and least no is said to be zero and repeated twice so only 48 numbers are non zeroes and greatest no is 20+0 we are asked to get 47 numbers average so omitting 0,0,20 form 50 numbers then deduction in sum would be 490-20=470 then average of 47 numbers would be 470/47=10 answer will be 10
• 11 years agoHelpfull: Yes(0) No(0)