When 2^256 is divided by 17 the remainder would be

• 2^4 / 17 => remainder = - 1
  2^8 / 17 => 1
  2^12/ 18 => - 1
  
  => for 2^4n / 17,
  (Rem = -1) if n is odd
  (Rem = +1) if n is even
  
  => 2^256 divided by 17 gives remainder +1
• 11 years agoHelpfull: Yes(28) No(1)
• 2^0=1
  2^1=2
  2^2=4
  2^3=8
  2^4=16
  Here after this the unit place is going to repeat again,so we will divide 256by 4 we get reminder=0. and 2^0=1 so 2^256 divided by 17,the reminder would be 1.
• 11 years agoHelpfull: Yes(1) No(1)
• 17 hase 16 co prime numbers
  so 2^16%17=1
  sam 2^16^16%17=1
• 11 years agoHelpfull: Yes(1) No(0)
• 2^256=(2^4)^64 then
  we have (2^$/17)^64 ,
  2^4/7 remainder = -1 or 16, take -1 then we have (-1)^64=1
  remainder=1
  
• 8 years agoHelpfull: Yes(0) No(0)