Elitmus
Exam
Numerical Ability
Number System
i mean set of 4 consequative no like 1+2+3+4=10/10
6+7+8+9=30/10 like this
Read Solution (Total 5)
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- 200 sets
If u mean set of consecutive 4 numbers, then
all set of numbers
(5n+1, 5n+2,5n+3,5n+4 ) will satisfy the condition.
so from n=0 to n=199.
200 sets are possible. - 11 years agoHelpfull: Yes(37) No(0)
- 200 sets
as there are 2 set from 1 to 10 accordingly there are 20 set between 1 to 100 and accordingly there are 200 set between to 1000 - 11 years agoHelpfull: Yes(7) No(0)
- 11+12+13+14=50/10;
16+17+18+19=70/10;
21+22+23+24=110/10;
31+32+33+34=130/10; - 11 years agoHelpfull: Yes(2) No(2)
- 1+2+3+4=10
6+7+8+9=30
11+12+13+14=50
16+17+18+19=70
21+22+23+24=90
thus all 5 sets from 1-100
50 sets from 1-1000 - 11 years agoHelpfull: Yes(0) No(3)
- 26+27+28+29=110
- 11 years agoHelpfull: Yes(0) No(2)
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