GRE
Exam
Numerical Ability
Averages
the average weight of 36 students is 50 kg . it was found later that the figure of 37kg was misprinted as 73kg.waht is the correct average.
Read Solution (Total 5)
-
- Total difference in sum of weight of 36 children = 73-37= 36 kg
so difference in average weight of 36 children = 36/36= 1 kg
so actual average weight is 50-1=49 kg - 11 years agoHelpfull: Yes(16) No(1)
- avg wt of 36 students = 50kg
total wt of 36 students = 50*36 =1800 kg
correct total wt of 36 students = 1800-73+37 = 1764 kg
correct avg wt = 1764/36 = 49 - 11 years agoHelpfull: Yes(11) No(3)
- 49 kg
Total misprinted weight = 36 x 50 = 1800 kg
Removing 73 kg and adding 37 kg
=> True total weight = 1800 - 73 + 37 = 1764
=> True average = 1764 / 36 = 49 kg - 11 years agoHelpfull: Yes(5) No(2)
- Ans 49 kg . Average of 36 students is 50 kg , therefore total weight = 36x 50 = 1800kg. 1800 -73(misprinted)+ 37 = 1764 kg . Real Average = 1764/36 = 49 kg
- 11 years agoHelpfull: Yes(3) No(1)
- 1333
new value= 37+36*36=11333 - 4 years agoHelpfull: Yes(0) No(0)
GRE Other Question
what is the mathematical average of the number of weeks in a year , seasons in a year and the number of days in january of that year
a student receives his grades report from a local community college,but the GPA is smudged.he took the following classes : a 2hr credit art, 3hr credit history, 4hr credit science,3hr credit in maths and 1hr credit in science lab. he received a 'B'in art,'A' in history,a 'C'in science,a'B' in math,a 'A' in science lab. what was his GPA if the letter grades are based on 4 point scale (A=4, B=3, C=2, D=1, F=0)