find the remainder when 2^ 30 is divided by 5

• 2^30 = (2^10)^3= 1024^3... last digit will be 4.
  
  so remainder is 4 when 4 is divided by 5 or 2^30 is divided by 5.
• 11 years agoHelpfull: Yes(8) No(2)
• 4 Since 2^ 30 = (2^4)^7 x 2^2.When 2^1 Remainder is 2 , 2^2 Remainder is 4, 2^3 Remainder is 3, 2^4, Remainder is 1, 2^5 Now Remainder chain is repeated i.e. 2.
  Hence After (2^4)^7 Remainder is repeated like 2^1 Remainder is 2 , 2^2 Remainder is 4.Hence it is confirmed that Remainder is 4
• 11 years agoHelpfull: Yes(1) No(3)
• 4 because 2^10^3=1024^3 so cubing of again we get 4 so remainder is 4
• 11 years agoHelpfull: Yes(1) No(2)
• (2^3)^10=8^10/5=3
• 11 years agoHelpfull: Yes(1) No(0)
• 2^30 = 2^2*2^3*2^5 = 1024
  =1024/5
  remainder=4
• 6 years agoHelpfull: Yes(0) No(0)