A1B2C3=FH
D1E2F3=OQ
G1H2I3=??

• or simply
  fh=6,8
  oq=15,17
  f~o=h~q=9
  so 15+9,17+9=24,26=x,z
• 11 years agoHelpfull: Yes(2) No(0)
• G1H2I3=XZ
  
• 11 years agoHelpfull: Yes(1) No(0)
• a=1,b=2,c=3...,z=26
  
  abc=fh-> 1 2 3= 6(1+2+3) 8(digit1+2)
  def=oq-> 4 5 6=15(4+5+6) 17(digit1+2)
  ghi=xz-> 7 8 9=24(7+8+9) 26(digit1+2)
  so g1h2i3=xz
• 11 years agoHelpfull: Yes(1) No(0)
• A1B2C3=FH A1=1X1=1;B2=2X2=4;C3=3X3=9::A1+B2+C3=14:::FH=6+8=14----diff b/w F&H is 2
  
  D1E2F3=OQ D1=4X1=4;E2=5X2=10;F3=6X3=18::D1+E2+F3=32::OQ=15+17=32---diff b/w O&Q is 2
  
  G1H2I3=?? G1=7X1=7;H2=8X2=16;I3=9X3=27::G1+H2+I3=50:: in order to make LHS 50 possible combination with difference 2 is XZ=24+26;
• 11 years agoHelpfull: Yes(1) No(0)