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15.******* The bacteria had a probability of splitting into three and a probability to die is one third of total bacteria. Let the probability be P. Some of them survived with probability 1/5 than which among the following relation is true?
(a) P=1/3+1/53
(b) P=1/5(1/8-3)

Read Solution (Total 1)

here prob for dying = 1/3
hence prob of survival = 1/5
if they survive, they will be splited into 3 more bacteria
hence, p = (1/3) + (3* 1/5)
10 years agoHelpfull: Yes(4) No(0)

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